Find the sum of all coefficients in the following binomial expansion.
a. (2u + v)^10
b. (2u − v)^10
c. (2u − 3v)^11
d. (u − 3v)^11
e. (1 + i)^10
f. (1 − i)^10
g. (1 + i)^200
h. (1 + i)^201

We can find the sum of all the coefficients by substituting all the variables in the expansion with one.

a. u=1,v=1

sum==

b.u=1,v=1

sum==1

c.u=1,v=1

sum==-1

d.u=1,v=1

sum==-

e.i=1

sum==

f.i=1

sum==0

g.i=1

sum==

h.i=1

sum==

it’s supposed to be -4+45=41

step-by-step explanation:

answer: the four apples you took away.

step-by-step explanation: