Nasa is conducting an experiment to find out the fraction of people who black out at g forces greater than 6. in an earlier study, the population proportion was estimated to be 0.46. how large a sample would be required in order to estimate the fraction of people who black out at 6 or more gs at the 98% confidence level with an error of at most 0.03?

1499

Step-by-step explanation:

As per given , we have

Prior Population proportion :

Significance level :

Critical value for 98% confidence interval (refer to z-value table) =

Margin of error :

Formula for sample size :

Therefore , the required minimum sample size = 1499

3x + 18 = 147°

step-by-step explanation:

3x + 18 = 147°, because the value of the central angle is equal to the value of the arc formed by it.

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step-by-step explanation: