Apedestrian walks at a rate of 6 km per hour east. the wind pushes him northwest at a rate of 13 km per hour. find the magnitude of the resultant vector.
(round to the nearest hundredth)

The pedestrian vector would be (6,0)

The wind vector would be (-13cos(45), 13sin(45))  =  (-9.1924, 9.1924)  

Now add the two vectors:  (6, 0) + (-9.1924, 9.1924)  =  (-3.1924, 9.1924)    

This is the resultant vector in rectangular coordinates.   Now calculate the magnitude of the vector.

Magnitude is always positive and  is : sqrt[x-coord2 + y-coord2]  

Magnitude = sqrt(94.6915599) = 9.73 ( rounded to the nearest hundredth)

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.

its kind of blurry. can you put a clearer pic?

step-by-step explanation: