Arectangular field will be fenced on all four sides. there will also be a line of fence across the field, parallel to the shorter side. if 900 meters of fencing are available, what dimensions of the fiels will produce the maximum area? what is the maximum area?

150m by 300 m

Step-by-step explanation:

150×300=45000

all sides add up to 900m

150+150+300+300

the answer is actually

Step-by-step explanation:

W:150m

L:225m

A:33750m^2

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point