Given the following system of equations: 2x + 6y = 12 4x + 3y = 15 which action creates an equivalent system that will eliminate one variable when they are combined? multiply the second equation by −2 to get −8x − 6y = −30. multiply the first equation by 2 to get 4x + 12y = 24. multiply the second equation by −4 to get −16x − 12y = −60. multiply the first equation by −4 to get −8x − 24y = −48.

Multiply the second equation by −2 to get −8x − 6y = −30 and this can be determined by carefully observing both the equations.

Given :

System of equations: 2x + 6y = 12 ; 4x + 3y = 15

The following steps can be used to evaluate which action creates an equivalent system that will eliminate one variable when they are combined:

Step 1 - Write the system of equations.

2x + 6y = 12   --- (1)

4x + 3y = 15   --- (2)

Step 2 - Now, multiply -2 in equation (2).

(4x + 3y = 15) -2

Step 3 - Further simplify the above equation.

-8x - 6y = -30  --- (3)

Step 4 - Now, add equation (1) and equation (3).

2x + 6y - 8x - 6y = 12 - 30

-6x = -18

x = 3

From the above steps, it can be concluded that the correct option is A) Multiply the second equation by −2 to get −8x − 6y = −30.

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Multiply the second equation by −2 to get −8x − 6y = −30.

Step-by-step explanation:

{2x + 6y = 12

{4x + 3y = 15

{2x + 6y = 12

{−8x − 6y = −30 >> New Equation

* Doing this will give you additive inverses of −6y and 6y, which result in 0, so they are both ELIMINATED.

** [3, 1] is your solution.

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what are the options? ?

step-by-step explanation:

answer is 67%

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