Match each function with the corresponding function formula when h(x) = 5 - 3x and g(x) = -3 x + 5.

1.

k(x) = (3h - 5g)(x)

2.

k(x) = (h - g)(x)

3.

k(x) = (5g + 3h)(x)

4.

k(x) = (3g + 5h)(x)

5.

k(x) = (g + h)(x)

6.

k(x) = (5h - 3g)(x)

To match each functions with the corresponding function formula when h(x) = 5 - 3x and g(x) = -3 x + 5.

1. k(x) = (3h - 5g)(x)

  = = 3(5 - 3x)-5(-3 x + 5)

 = = 15 - 9x + 15x - 25

  K(x) = -10 + 6x

2.  k(x) = (h - g)(x)

    = = (5 - 3x) - (-3 x + 5)

 = = 0

k(x) = 0

3. k(x) = (5g + 3h)(x)

 = = 5(-3 x + 5)+3(5 - 3x)

 = = -15x + 25 + 15 - 9x

 k(x) = - 24x +40

4. k(x) = (3g + 5h)(x)

  =  = 3 (-3 x + 5) + 5(5 - 3x)

 = = -9x + 15 +25 -15x

 k(x) = -24x + 40

5.  k(x) = (g + h)(x)

   = = (-3 x + 5) + (5 - 3x)

k(x)  = -6x + 10

6.  k(x) = (5h - 3g)(x)

 = = 5(5 - 3x) - 3(-3 x + 5)

= =25 - 15x + 9x - 15

k(x) = 10 - 6x

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: