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given: ⎺wj = ⎺kz. ∠w and ∠k are right angles. prove: △jwz = △zkj

The two triangles are congruent by HL postulate.

Step-by-step explanation:

Given:

The two triangles Δ JWZ and Δ ZKJ are right angled triangles.

Angles W and K are right angles, therefore by definition of right angles they are equal to 90 degrees.

WZ = KZ [Given]

JZ = JZ [Reflexive property of sides]

JZ is the hypotenuse of both the triangles.

WZ and KZ are the legs.

So, the two right angled triangles are congruent by HL postulate. 'H' means Hypotenuse and 'L' means Leg.

Therefore, the two triangles  Δ JWZ and Δ ZKJ  are congruent. Hence it is proved.

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3