Observe that the integral in the normalization condition can be separated into angular and radial components: ∫[infinity]0∫π0∫2π0|a1e−r/a|2r2sin( θ)dϕdθdr=[∫[infinity]0|a1e−r/a|2r2d r](∫π0∫2π0sin(θ)dϕdθ). find the value of the angular double integral (the expression in parentheses). express your answer in terms of π.

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

well your weight will go up if you are not going to burn the calories/ carbs

step-by-step explanation:

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