Asquare poster has sides measuring 2 feet less than the sides of a square sign. of the difference between their areas is 36 square feet, find the lengths of the sides of the poster and sign

The length of the side of the square poster is 8 feet

The length of the side of the square sign is 10 feet

Step-by-step explanation:

Let the length of one side of the square poster be x

Let the length of one side of the square sign be y

Since they are both squares, the area of a square is expressed as length^2

A square poster has sides measuring 2 feet less than the sides of a square sign. It means that

y = 2+x

If the difference between their areas is 36 square feet, it means that

y^2 - x^2 = 36 - - - - - - - 1

Substituting y = 2 + x into equation 1, it becomes

(2+x)^2 - x^2 = 36

4 + 4x + x^2 - x^2 = 36

4x = 36 - 4 = 32

x = 32/4 = 8

y = 2 + x = 2 + 8

y = 10

answer: no

step-by-step explanation: because the big angle will spread away the 2 side that it is on and make the opposite side even longer.