If ab is the diameter of the circle with center x and c is a point on the circle such that ac = ax = 3, what is the perimeter of triangle abc ?

Step-by-step explanation:

The perimeter of a shape or plane figure is the distance round the shape. The diagram of the circle and the triangle ABC formed is shown in the attached photo.

To determine the length of AC, we would apply the Pythagoras theorem which is expressed as follows

Hypotenuse^2 = opposite ^2 + adjacent ^2

AC = hypotenuse

Opposite = 3

Adjacent = 3

AC^2 = 3^2 + 3^2 = 9 + 9 = 18

AC = √18 = 4.24

BX = AX = 3(they are both radii)

BC = AC = 4.24

The perimeter of triangle ABC would be

3 + 3 + 4.24 + 4.24 = 14.48

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13