Find three consecutive even integers such that the sum of the first, twice the second, three times the third is -76. what is the number?
(the three numbers is the same number)

The numbers are -14,-13 and -12

Step-by-step explanation:

The correct question is

Find three consecutive integers such that the sum of the first, twice the second and three times the third is -76. What is the number?

Let

x ----> the first consecutive integer

x+1 ---> the second consecutive integer

x+2 ---> the third consecutive integer

we have that

solve for x

apply distributive property

Combine like terms

subtract 8 both sides

Divide by 6 both sides

so

therefore

The numbers are -14,-13 and -12

idk

step-by-step explanation: