Aquadrilateral has vertices (2 + √2, −1), (8 + √2, 3), (6 + √2, 6), and (√2, 2). prove that the quadrilateral is a
rectangle.

As the opposite lines have the same slope and are equal in lengths. It is proved that the quadrilateral with given points is indeed a rectangle!

Step-by-step explanation:

The condition for a quadrilateral to be a rectangle is that

Given the points A(2 + √2, −1), B(8 + √2, 3), C(6 + √2, 6), and D(√2, 2)

We don't know in what order they are given, so our first step should be to calculate the distances using the distance formula:

distance AB

distance BC

since these two distances are different, the next two SHOULD be equal to AB and BC

distance CD

distance DA

Now we have an idea that since AB = CD and BC = DA, then if this shape is a rectangle then these opposite lines should also be parallel to each other!

Hence we need to see if:

slope of AB = slope of CD

and

slope of BC = slope of DA

to find the slope between two points, we'll use

checking: slope of AB = slope of CD:

hence the lines AB and CD are parallel and equal!

we can do the same for BC and DA

slope of BC = slope of DA

hence the lines BC and DA are parallel and equal as well!

i am unable to solve this problem

step-by-step explanation: