Mathematics, 14.01.2020 22:31 jayzelgaspar8005

Using integration by parts,
∫1/x dx = ∫1/x.1 dx
= ∫1/x. x-∫(-1/x^2)x dx
= ∫1+∫1/x dx.
subtracting ∫1/x dx from both sideswe conclude that 0=1. what is wrong with this logic?

Answers: 3

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Using integration by parts,
∫1/x dx = ∫1/x.1 dx
= ∫1/x. x-∫(-1/x^2)x dx
= ∫1+∫1/x...

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More questions: Mathematics Another questions

Using integration by parts, ∫1/x dx = ∫1/x.1 dx = ∫1/x. x-∫(-1/x^2)x dx = ∫1+∫1/x dx. subtracting ∫1/x dx from both sideswe conclude that 0=1. what is wrong with this logic?

Answers

Another question on Mathematics

Using integration by parts,
∫1/x dx = ∫1/x.1 dx
= ∫1/x. x-∫(-1/x^2)x dx
= ∫1+∫1/x dx.
subtracting ∫1/x dx from both sideswe conclude that 0=1. what is wrong with this logic?