Two payment options to rent a car: you can pay $20 a day plus 25¢ a mile (option a) or pay $10 a day plus 50¢ a mile (option b). for what amount of daily miles will option a be the cheaper plan?

You must drive more than 40 miles to make option A the cheaper plan

Solution:

Two payment options to rent a car

Let "x" be the number of miles driven in one day

You can pay $20 a day plus 25¢ a mile (Option A)

25 cents is equal to 0.25 dollars

OPTION A :  20 + 0.25x

You pay $10 a day plus 50¢ a mile (Option B)

50 cents equal to 0.50 dollars

Option B: 10 + 0.50x

For what amount of daily miles will option A be the cheaper plan ?

For option A to be cheaper, Option A must be less than option B

Option A < Option B

Solve the inequality

Add -0.50x on both sides

Add - 20 on both sides,

Divide both sides by 0.25

Thus you must drive more than 40 miles to make option A the cheaper plan

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.