One of the solutions to x2 − 2x − 15 = 0 is x = −3. what is the other solution?

x = −5
x = −1
x = 1
x = 5

To answer the question above, divide the given second degree polynomial by the given solution. You may either use the long division or the synthetic division. Using the long division, 
                                   
                                           (x^2 - 2x -15) / (x + 3) = x - 5

Thus, the other solution is x - 5 or x = 5 which is the last one from the given choices. 
                                         
                                

To answer the question above, divide the given second degree polynomial by the given solution. You may either use the long division or the synthetic division. Using the long division, 
                                   
                                           (x^2 - 2x -15) / (x + 3) = x - 5

Thus, the other solution is x - 5 or x = 5 which is the last one from the given choices.