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the equation y-5-6(x+1) is written in point-slope form. what is the equation written in slope-intercept form?

y = 6x + 11

Step-by-step explanation:

The slope-intercept form ⇒ y = mx + c

Where m is the slope and c is y-intercept

So, we need to change point-slope form to slope-intercept form

The given equation:  y - 5 = 6 (x+1)

∴ y - 5 = 6x + 6     add 5 to each side of the equation

∴ y = 6x + 6 + 5

∴ y = 6x + 11

So, the equation written in slope-intercept form is y = 6x + 11

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.