Judging from recent experience, 5% of the computer keyboards produced by an automatic, high-speed machine are defective. if six keyboards are randomly selected, what is the probability that none of the keyboards are defective?

0.7351

Step-by-step explanation:

We use Binomial distribution here , where the probability of getting x successes in n-trials is given by :-

, p= Probability of getting success in each trial.

As per given , the proportion of computer keyboards produced by an automatic, high-speed machine are defective : p=0.05

n=6

Let x be the number of defective keyboards.

The probability that none of the keyboards are defective will be :

Hence, the probability that none of the keyboards are defective is probability that none of the keyboards are defective is 0.7351 .

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)