Acardboard box manufacturing company is building boxes with length represented by x+ 1, width by 5- x, and height by x -1. the volume of the box is modeled by the function below v(x) 18 14 10 6 24 x 5 6 2 2 3 -2 -6 over which interval is the volume of the box changing at the fastest average rate? [1,2] a. [1,3.5 b. c. [1,5] r0,3.51 d

a. [1,2]

b. [1,3.5]

c. [1,5]

d. [0,3.5]

So then we can conclude that the highest slope is for the interval [1,2] and that would be our solution for the fastest average rate.

a. [1,2]

Step-by-step explanation:

Assuming that we have the figure attached for the function. For this case we just need to quantify the slope given by:

For each interval and the greatest slope would be the interval on which the volume of the box is changing at the fastest average rate

a. [1,2]

b. [1,3.5]

c. [1,5]

d. [0,3.5]

So then we can conclude that the highest slope is for the interval [1,2] and that would be our solution for the fastest average rate.

a. [1,2]

da freeck kinda math is this just drop out

step-by-step explanation:

answer: a. 13/44

step-by-step explanation: judging by the information given to us, we are looking for experimental probability. we can see that 13 males have chosen chocolate ice cream. there are 44 ice creams in total (remember that the total is always the denominator). so our answer is 13/44.