Kinda confused with this, how am i supposed to answer for x if in (-4 + 41) there’s no

x=13 and y=20.

Step-by-step explanation:

76 is what u use to try to find both variables. So...u set it up as 6x-2=76. You add 2 to both sides. The 2 cancels out. 6x=78. Divide by 6. x=13. On the other hand, set the other equation as (-4+4y)=76. open the parenthesis...-4+4y=76. add 4 to both sides. 4y=80. Divide by 4 on both sidesy=20. Reason why u couldnt see x is because the x looks faded with the numbers.

step-by-step explanation:

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b