Find the value of s(t(-5)):
s(x) = - 3x-2
t(x)=5x - 4

s(t(-5)) First find t(-5), since you know x = -5, substitute/plug in -5 for x in t(x) = 5x - 4

t(x) = 5x - 4

t(-5) = 5(-5) - 4

t(-5) = -25 - 4

t(-5) = -29

s(t(-5)) plug in -29 for t(-5)

s(-29) = -3(-29) - 2 (- times a - equals a positive)

s(-29) = 87 - 2

s(-29) = 85

Your answer is 85

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

think about it deeply and passionately about this property

i am sorry