writing the equation of
a
what is the equation of a line that is parallel to the line 2x + 5y = 10 and passes through the point (-5, 1)? check all
that apply.
y=-2x-1
2x + 5y = -5
y=-2x-3
2x + 5y = -15
1= -2.(x + 5)

2x + 5y = -5

Step-by-step explanation:

Two lines are said to be parallel if they have the same slope.

The equation of the line given :

2x + 5y = 10

To find the slope , we will write it in the form y = mx + c , where m is the slope and c is the y - intercept.

2x + 5y = 10

5y = -2x + 10

y = -2/5x + 10/5

y = -2/5x + 2

This means that the slope is -2/5 ,the line that is parallel to this line will also have a slope of -2/5.

using the formula:

= m ( ) to find the equation of the line , we have

y - 1 = -2/5(x -{-5})

y - 1 = -2/5 ( x + 5 )

5y - 5 = -2 ( x + 5 )

5y - 5 = -2x - 10

5y + 2x = -10 + 5

therefore :

2x + 5y = -5 is the equation of the line that is parallel to 2x + 5y = 10

2x + 5y = -5

Step-by-step explanation:please see attachment for explanation

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

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