Write a function rule for the area of a rectangle whose length is 7 ft more than its width. what is the area of the rectangle when it’s width is 8ft?

  is the rule for the area of a rectangle.

A = 120 sq ft, when it’s width is 8 ft.

Step-by-step explanation:

Here, let us assume the width of the rectangle =  w

So, the length here = Width +  7 ft = (w +  7) ft

Now, AREA of a RECTANGLE = Length x Width

Substituting here the values of length and width, we get:

A = (w) x (w +  7)

The above function is the rule for the area of a rectangle.

Given: w = 8  ft

To find the area: put w  = 8 in

We get: A  = 8²  +  7(8)  

                 = 64 +  56  = 120

or, A  = 120 sq ft.

Hence, area = 120 sq ft, when it’s width is 8 ft.

529 and 531

step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°