The perimeter of a rectangle sandpit is 40 meters. The length of the sandpit is 1 meter less than twice it's width. What are the dimensions of this sandpit

L = 15, W = 8

Step-by-step explanation:

Perimeter = 2(L + W)

P = 40

L = 2W - 1

40 = 2((2W-1) + W)

40 = 4W - 2 + 2W

40 = 6W - 2

42 = 6W

W = 8

Since L = 2W - 1

L = 2(8) - 1

L = 15

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)