A mass is attached to a spring with spring constant k = 20 N/m . The spring is stretched to 10 cm past its resting position. How much work (in J) does the spring do when the object is released and the mass travels back to its initial position?

0.1J

Step-by-step explanation:

From the expression given by Scientists Robert Hook, it clearly states that two forms of energy is associated with the mass released from the spring, namely the kinetic energy and the potential energy.

The expression for the kinetic energy is

K.E=1/2mv^2

While the potential energy is

P.E=1/2kx^2

Where K is the spring constant and X is the extention. If we substitute the data given in the question we arrive at

P. E=1/2(20*0.1^2)

P.E=0.1J

Hence the amount of work done is 0.1J

the answer to the expression is 83

25 questions , because they start with 100.  

350-100=250 .  

. 250/10=25

step-by-step explanation:

first take off 100, then what x 10 = 250? that is your answer. (25)