A certain shop repairs both audio and video components. Let A denote the event that the next component brought in for repair is an audio component, and let B be the event that the next component is a compact disc player (so the event B is contained in A). Suppose that P(A) 1?4 .6 and P(B) 1?4 .05. What is P(B | A)?

The correct answer is, P (B | A) = 0.0833.

Step-by-step explanation:

It is provided that:

A = the event that the next component brought in for repair is an audio component.

B = the event that the next component is a compact disc player

The event B is contained in A. This implies that P (B) = P (A and B) .

P (A) = 0.60 and P (B) = P (A and B) = 0.05.

According to the conditional probability rule:

Determine the probability of the event (B | A) is:

Thus, the probability of event B given event A is 0.0833.

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol