Suppose a triangle has sides 3, 4, and 6. which of the following must be true?

Answer with explanation:

Sides of triangle are , 3, 4 and 6.

This is an Isosceles triangle,because all the three sides are not equal to each other.

Length of Greatest Side= 6 cm

Length of other two smaller sides are 3,and 4 cm.

Sum of square of two smaller sides

    = 3²+4²

    = 9 + 16

    = 25

Square of largest side = 6²=36

36≠25

Square of largest side≠Sum of squares of two smaller sides

Pythagorean theorem not verified.

Hence ,the triangles having sides, 3, 4 and 6 is not a right triangle.

the answer is a

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.