A rational function of the form y = a/(x - h) + k has asymptotes at x = 4 and y = - 2.
Write the equations of two different functions that meet this description.

y = 2/(x-4) - 2

y = 3/(x-4) - 2

Step-by-step explanation:

asymptote x = 4, when (x-4) in the denominator

asymptote y = -2 when the quotient (whole number, outside the fraction is -2)

y = a/(x-4) - 2, where a is not 0

Two functions could be:

y = 2/(x-4) - 2

y = 3/(x-4) - 2

answer: 2530

hope this

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.