Prove the theorem (AB)^T = B^TA^T.

Complete the first step of the proof by filling in the blank.

The (i, j)-entry of (AB)^T is the (j, i)-entry of AB, which is a_j1 b_1i +... + a_jn b_ni.

Complete the second step of the proof by filling in the blank.

The entries in row i of B^T are b _1i, b_ni.

Complete the third step of the proof by filling in the blank.

The entries in column j of A^T are a_j1, a_jn.

Complete the fourth step of the proof by filling in the blank.

The (i, j)-entry in B^TA^T is a_j1 b_1i +... + a_jn b_ni.

Write a conclusion by filling in the blank.

Therefore. (AB)^T = B^TA^T.

2. angles qrt and qst both measures 156 degrees.

step-by-step explanation:  

we have been given a diagram of a circle and we are told that measure of arc qvt is 156 degrees.  

we can see from our given diagram that angle qrt and angle qst subtends to arc qvt.

since we know that angles subtended by the same arc at the circumference are always equal.

by angle subtended by same arc theorem, measure of angle qrt and angle qst will be equal to the measure of arc qvt.

therefore, angles qrt and qst both measures 156 degrees and 2nd statement is the correct choice.

0.32

step-by-step explanation:

2.24/7

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)