Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 16 feet and a height of 18 feet. Container B has a diameter of 22 feet and a height of 15 feet. Container A is full of water and the water is pumped into Container B until Container A is empty. After the pumping is complete, what is the volume of water in Container B, to the nearest tenth of a cubic foot?

Step-by-step explanation:

We must first determine the volume of cylinder A and the volume of cylinder B

Now if the content of cylinder A passes to cylinder B, this means that the volume of water that was in cylinder A is equal to the volume of cylinder B since all the water in A passed to B

, therefore the volume of water in B is 5701.99 ft3, and the nearest tenth of cubic foot will then be 5702 ft3

answer for #1 is c

answer for #2 is d

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step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?