Determine the number of standard deviations that includes all data values listed for the situation. The mean height of a tree in an orchard is 11.8 feet; the standard deviation is 1.43 feet. 12.5 ft, 9.8 ft, 13.5 ft, 11.2 ft, 12.3 ft, 14.2 ft, 11.7 ft, 9.8 ft, 12.6 ft, 10.4 ft

Therefore the number of standard deviation is 1.41 ft.

Step-by-step explanation:

Mean: The average of all numbers is known as mean.

To find out the number of standard deviation,

Given mean of the orchard tree is 11.8.

Given distribution is 12.5 ft, 9.8 ft, 13.5 ft,11.2 ft, 12.3 ft , 14.2 ft, 11.7 ft, 9.8 ft , 12.6 ft, 10.4 ft.

In order to get the number of standard deviation, we have to subtract mean from each number .

Then (12.5-11.8)ft,(9.8-11.8)ft , (13.5-11.8)ft,(11.2-11.8) ft, (12.3-11.8) ft , (14.2 -11.8)ft, (11.7 -11.8)ft,( 9.8-11.8) ft , (12.6-11.8) ft,( 10.4-11.8) ft.

=0.7 ft, -2.0 ft,1.7 ft, -0.6 ft,0.5 ft,2.4 ft, -0.1 ft , -2.0 ft,0.8 ft,-1.2 ft

Therefore the number of deviation is

= 1.4085

≈1.41

Therefore the number of standard deviation is 1.41 ft.

mean, 40.6

step-by-step explanation:

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-aparri