If logb2=x and logb3=y, evaluate the following in terms of x and y:

(a) logb162=
(b) logb324=
(c) logb8/9=
(d) logb27/logb16

Solution:

Given that,

Use the following log rules

Rule 1:

Rule 2:

Rule 3:

Break 162 down to primes:

Thus we get,

Next

Break 324 down to primes:

Next

By rule 2

Next

By rule 2

Thus the given are evaluated in terms of x and y

goog may have it for you

{3 + i, 3 - i, 3, -1}

step-by-step explanation: