The table represents an exponential function.

A 2-column table has 4 rows. The first column is labeled x with entries 1, 2, 3, 4. The second column is labeled y with entries 2, two-fifths, StartFraction 2 Over 25 EndFraction, StartFraction 2 Over 125 EndFraction.

What is the multiplicative rate of change of the function?

One-fifth
Two-fifths
2
5

answer:

3/4

Step-by-step explanation:

x |  y

1  | 3/2

2 | 9/8

3 | 27/32

4 |  81/128

\frac{\frac{9}{8}}{\frac{3}{2}}=\frac{9}{8} \div \frac{3}{2}=\frac{9}{8} \cdot \frac{2}{3}=\frac{18}{24}=\frac{18 \div 3}{24 \div 3}=\frac{6}{8}=\frac{6 \div 2}{8 \div 2}=\frac{3}{4}

So the multiplicative rate of change of this function is \frac{3}{4} .

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.