Chisaka has less than 145 145145 kg kgstart text, space, k, g, end text of food remaining in her spaceship. She needs a constant amount of food each day that she spacewalks, and a constant amount of food each day that she doesn't spacewalk. Let S SS represent the number of days Chisaka spacewalks and N NN represent the number of days she doesn't spacewalk without running out of food. 2.2 S + 1.3 N < 145 2.2S+1.3N<1452, point, 2, S, plus, 1, point, 3, N, is less than, 145 According to the inequality, how much food does Chisaka need for each day that she does and doesn't spacewalk? Chisaka needs kg kgstart text, k, g, end text of food for each day that she spacewalks, and kg kgstart text, k, g, end text of food for each day that she doesn't spacewalk. Can Chisaka spacewalk for 30 3030 days and not spacewalk for 50 5050 days without running out of food? Choose 1

2.2 kg food for each day of spacewalk.

1.3 kg food for each day when she doesn't spacewalk.

Chisaka can spacewalk for 30 days and not spacewalk for 50 days without running out of food.

Step-by-step explanation:

We have been given an inequality , where S represent the number of days Chisaka spacewalks and N represent the number of days she doesn't spacewalk without running out of food.

We are asked to find the amount of food Chisaka need for each day that she does and doesn't spacewalk.

Since S represent the number of days Chisaka spacewalks, so will represent amount of food Chisaka needs for S days of spacewalk.

Therefore, Chisaka needs 2.2 kg of food for each day of spacewalk.

Since N represent the number of days Chisaka doesn't spacewalks, so will represent amount of food Chisaka needs for N days when she doesn't spacewalk.

Therefore, Chisaka needs 1.3 kg of food each day when she doesn't spacewalk.

To find that Chisaka can spacewalk for 30 days and not spacewalk for 50 days without running out of food, we will substitute and in our given inequality as:

We can see that Chisaka needs 131 kg of food for 30 day of spacewalk and 50 days with out spacewalk.

Since 131 kg is less than 145 kg, therefore, Chisaka can spacewalk for 30 days and not spacewalk for 50 days without running out of food.

over the argument its not good to fight.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.