Frank started travelling 45 mph. When Frank was 1/3 miles away, Daniel started from the same point at 50 mph to catch up with Frank. How long will it take Daniel to catch up to Frank?

Step-by-step explanation:

Initial velocity of frank=45mph,

Now frank at a distance 1/3miles

Daniel started with a speed of 50mph,

Let Daniel catch up with Frank at time t

Speed = distance/time

Time=distance/speed

For frank, he has already traveled for a time of

t, =d/s

t=1/3÷50

t=1/150hour

Let now assume they meet at distance x,

Time for Daniel to reach x

t=d/s

t=x/50. Equation 1

Time for Frank to reach x, he has already traveled 1/3 miles, then he has x-1/3miles to travelled

t=d/s

t=(x-1/3)÷45. Equation 2

Then both time are same, let equate them

time frank =time Daniel

x/50=(x-1/3)/45

45x=50(x-1/3)

45x=50x-50/3

45x-50x=-50 /3

-5x=-50/3

x=50/3÷5

x=10/3

x=3.333miles

They will meet at 3.3333miles, not to know the time, let substitute into equation 1

t=x/50

t=3.33333/50

t=0.0667hours

Or t=4secs

answer: a. 13/44

step-by-step explanation: judging by the information given to us, we are looking for experimental probability. we can see that 13 males have chosen chocolate ice cream. there are 44 ice creams in total (remember that the total is always the denominator). so our answer is 13/44.

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