A jogger begins her workout by jogging to the park, a distance of 21 miles. She then jogs home at the same speed, but along a different route. This return trip is 28 miles, and her time is one hour longer. Find her jogging speed. Complete the accompanying chart and use it to find her jogging speed. Let r be the jogging speed.

She jogs at a speed of 7mph

Step-by-step explanation:

Distance to the Park=21 miles

Let her Speed be r( miles/hour)

Time taken= t hour

Therefore her Speed, r= 21/t (I)

Distance on her Return Trip= 28 miles

On her return trip, the time is 1 hour longer, therefore time taken=(t+1) hour

Speed , r =28/(t+1) (ii)

Since her speed is the same

21/t=28/(t+1)

Cross Multiplying

21(t+1)=28t

21+21t=28t

21=28t-21t

21=7t

Therefore her time, t=3

From (I),

Speed r= 21/t= 21/3 =7 miles per hour

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation: