A sample of 12 small bags of the same brand of candies was selected. Assume that the population distribution of bag weights is normal. The weight of each bag was then recorded. The mean weight was 3 ounces with a standard deviation of 0.13 ounces. The population standard deviation is known to be 0.1 ounce.
NOTE: If you are using a Student's t-distribution, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.)

Find the following. (Round your answers to two decimal places.)

(i) x =
(ii) σ =
(iii) sx =

Step-by-step explanation:

Hello!

You have the variable:

X: Weight of a small bag of candies (ounces)

n= 12 small bags

i) Sample mean, X[bar]= 3 ounces

This is the expected weight of the small bags of candies.

ii) Population Standard deviation, σ= 0.1 ounces

The population standard deviation is a measurement of variability, it shows you how dispersed are the population values from the population mean.

iii) Sample standard deviation, S= 0.13 ounces

The sample standard deviation is the point estimate of the population standard deviation, it is a measure of variability, it shows the dispersion of the data around the sample mean.

I hope it helps!

80° is the measure of gh

step-by-step explanation:

circle f is congruent to circle j

we have two circle with center f and j.

both circles are congruent. the radius of the circle would be equal.

see the attachment for the circle.

we are given ∠efd ≅ ∠gjh

therefore, arc (ed) = arc (gh)     (∴ circle f is congruent to circle j)

but ∠dfe=80°=arc (ed)

therefore, arc (gh) = 80°

thus, 80° is the measure of gh

ιт ιѕ $222.95

step-by-step explanation:

αℓℓ уσυ gσт тσ ∂σ ιѕ fιgυяє συт ωнαт 30% σf $318.50 ιѕ $95.55

тнєи ѕυвтяα¢т ιт fяσм $318.50-$95.55=$222.95

нσρє ι ¢συℓ∂ нєℓρ уσυ συ