* Two cars started to move from C and from D, towards one another. The car that starts at point C moves twice as fast as the car that starts at point D. How far from Boston will these two cars meet?

The answer to the question is

If Boston is at D and C is 90 km away from Boston, then the two cars will meet at 30 km from Boston.

Step-by-step explanation:

Let the speed of the car that start from C = V₁

Let the speed of the car that start from D = V₂

Therefore where V₁ = 2·V₂

We have at time t when the cars meet the distance covered by the car that start from C will be V₁×t = 2·V₂×t, while the distance of the other car will be

V₂×t

Which means that the distance covered by the car that start from C is twice that of the car that start from D

Hence if Boston is located at D which is 90 km from C then both cars will meet at

90 km /3 = 30 km from Boston as the car originating from Boston would only have covered 30 km when the two cars meet.

it's d.

step-by-step explanation:

because: -1(4x + 1y) +2 (1x-3y) distribute each number into the parenthesis.

then you would get: -4x - 1y + 2x -6y combine like terms

and get: 2x -7y

hope my answer has you if not then i'm sorry.

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.