A particular dam contains approximately 1 comma 800 comma 000 comma 000 comma 000 cubic feet of water. For a week-long spikeflood, water was released at a rate of 25 comma 700 cubic feet per second.

a. How much water was released during the flood?

b. What percentage of the dam was released during the flood?

(a)15,543,360,000 cubic feet

(b)0.86%

Step-by-step explanation:

The dam contains approximately 1,800,000,000,000 cubic feet of water.

Water was released at a rate of 25,700 cubic feet per second

Since this is done for a week, we determine first the number of seconds in a week.

1 week =(7 X 24 X 60 X 60 ) seconds = 604,800 seconds

(a) Total Volume of Water Released During the Week

= 25700 X  604800 =15,543,360,000 cubic feet

(b)Percentage of the Dam Released

=

A) Volume of water released for the 1 week= =15,543,360,000 ft³

B) Percentage of water released for the 1 week = 0.864%

Step-by-step explanation:

From the question, we are given;Water contained by dam= 1,800,000,000,000 ft³

Rate at which water was released =25,700 ft³/s

Time for which water was released at that rate = 1 week.

Now, we have to convert this 1 week to seconds since the rate is in m³/s

Thus, 1 week = 7days/week x 24 hours/day x 60minutes/hour x 60 seconds/minute = 604,800 seconds

A) So, total volume of water released for this 1 week duration is;

= 25700 X  604800 =15,543,360,000 ft³

B) Percentage released = [(Volume of water released for the week)/(Volume of water contained in dam)] x 100% = (15,543,360,000/1,800,000,000,000) x 100%= 0.864%