Determine the equation of each of the following parabolas

Try this solution with a short explanation:

a) y=ax²+5; ⇒ substitution (4;0): 16a+5=0; ⇒ a= -5/16.

y= -5/16 x²+5;

b) y=x²;

c) y=ax(x+7); ⇒ substitution (4;4): 4a(4+7)=4; ⇒a=1/11.

y= 1/11 x²+ 7/11 x;

d) y=a(x-1)(x-3); ⇒substitution (0;3): (-1)*(-3)*a=3; ⇒a=1.

y=x²-4x+3;

e) y=a(x-1)(x+3); ⇒ substitution (-1;5): (-2)*2*a=5; ⇒ a= -5/4.

y= -5/4 x² -5/2 x +15/4;

f) y=ax²+bx+c; ⇒ substitution (2;2): 4a+2b+6=2 or 2a+b= -2 (the I-st equation of the system);

the x-coordinate of the vertex: -b/2a=2; ⇒ b= -4a (the II-d equation of the system);

y=x²-4x+6.

or

a. 32 degrees

step-by-step explanation:

here we have to use the rule.

m∠e = 1/2 (major arc - minor arc)

m∠e = 1/2 (212 - 148)

m∠e = 1/2 (64)

m∠e = 32 degrees

answer: a. 32 degrees

you