Out of the students in a class, 50% are geniuses, 60% love chocolate, and 30% fall into both categories. Determine the probability that a randomly selected student from the class is neither a genius nor a chocolate lover.

20% probability that a randomly selected student from the class is neither a genius nor a chocolate lover.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is a genius.

B is the probability that a men student likes chocolate.

C is the probability that a student is not a genius and does not like chocolate.

We have that:

In which a is the probability that a student is a genius but does not like chocolate and is the probability that a student is both a genius and likes chocolate.

By the same logic, we have that:

30% fall into both categories.

This means that

60% love chocolate

This means that . So

50% are geniuses

We know that either a student is at least a genius or likes chocolate, or a student is not a genius and does not like chocolate. The sum of the probabilities of these events is decimal 1. So

In which

We want C, so

20% probability that a randomly selected student from the class is neither a genius nor a chocolate lover.

12

step-by-step explanation:

a triangle's   full angle is 180 degrees so 180 - 156 = 24. 24/2=12

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)