F the distance to the bottom of the sun is approximately 90 million miles from Earth, and the angle of elevation to the top of the sun is 0.5 ∘ , find the diameter of the sun. Round to the nearest 10 , 000 miles.

790,000miles

Step-by-step explanation:

Given :

Angle of elevation = 0.5°

Distance = 90,000,000 miles

For the angle of elevation, we neet to convert it from degree to time.

Therefore to convert we use:

Angular size = 0.5°*(60min/degree)*(60seconds/min) =

= 0.5*60*60 = 1800 seconds of arc

Therefore, to find the diameter we use the formula:

Angular diameter= 206265 *(diameter of sun/distance)

Since we are looking for the diameter, we make it subject of the formula, we have:

Diameter of Sun= ( Angular diameter * distance) / 206265

Applying the formula we have:

(1800*90000000)/206265

= 785394.43

Which is approximately 790,000miles.

Therefore diameter of the sun is 790,000 miles

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6