Three cards are drawn with replacement from a standard deck. What is the probability that the first card will be a diamond, the second card will be a black card, and the third card will be a queen? Express your answer as a fraction or a decimal number rounded to four decimal places.

The probability that the first card will be a diamond, the second card will be a black card, and the third card will be a queen is 0.0096

Step-by-step explanation:

Total no. of cards = 52

No. of diamond cards = 13

No. of black cards = 26

No. of queens = 4

Three cards are drawn with replacement from a standard deck.

We are supposed to find he probability that the first card will be a diamond, the second card will be a black card, and the third card will be a queen

Probability of getting diamond card =

Probability of getting black card =

Probability of queen =

Probability  that the first card will be a diamond, the second card will be a black card, and the third card will be a queen =

Hence the probability that the first card will be a diamond, the second card will be a black card, and the third card will be a queen is 0.0096

14

step-by-step explanation:

14 x 3 = 42

25% is the answer