Neil has 3 partially full cans of white paint . They contain 1/3 gallon , 1/5 gallon and 1/2 gallon of paint. About how many paint does Neil have in all

31/30 gallons

Step-by-step explanation:

finding the lowest common denominator for all three numbers. so 1/3 becomes 10/30, 1/5 becomes 6/30, and 1/2 becomes 15/30. 10/30+6/30+15/30=31/30

31/30

Step-by-step explanation:

you have to first find a common denominator. Which in this case is 30 so then you have to multiply by the same number for both bottom and top number of the fraction. 1/3 = 10/30 1/5=6/30 1/2=15/30. Then, you just have to add JUST THE TOP NUMBERS. You get 31/30 then divide that and i will leave that last part to you. Hope this helps!

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

2nd one in the first row is correct