Find an equation of a line with slop -4 snd containing the point (-2,-1)

y = -4x - 9

Step-by-step explanation:

The formula to calculate the slope of a line is

m = (y - y1) / (x - x1)

And the gradient form of the equation of a line is given as

y = mx + c

y and x represent coordinates. Points are represented as (x, y)

In this question, we are given the value of m to be

m = -4

y1 = -1

x1 = -2

Now we have

m = [y - (-1)] / [x - (-2)]

-4 = (y + 1) / (x + 2)

We then cross multiply to get

y + 1 = -4(x + 2)

y + 1 = -4x + (-8)

y + 1 = -4x - 8

y = -4x - 8 - 1

y = -4x - 9

Therefore the equation of the equation of a line with slope -4 and containing the point (-2,-1) is

y = -4x - 9

answerthe vertex form

step-by-step explanation:

geometry: triangles

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lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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