You need to have a password with 4 letters followed by 3 even digits between 0 and 9, inclusive. If the characters and digits cannot be used more than once, how many choices do you have for your password?

21528000 choices

Step-by-step explanation:

Since there are 26 letters of the alphabet and no alphabet is to be used more than once,

then the first letter can be chosen in 26ways

Second letter can be chosen im 25ways

Third letter can be chosen in 24ways

Fourth letter can be chosen in 23ways.

Since we can only use even digits, then the even digits we have are "0,2,4,6,8"

Then the first digit can be chosen in 5ways

Second digit can be chosen in 4ways

Third digit can be chosen in 3ways.

Total number of choices for this pass word = 26×25×24×23×5×4×3 = 21528000 choices

steve should create a type of business report called a business plan. the correct option among the options that are already given in the question is the last or the fourth option. this business report created by steve will actually influence the investors about investing their money in steve's business. this business report will have all the details about the business, the amount of investment required and the amount of expected profit.

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1