Suppose the germination periods, in days, for grass seed are normally distributed. If the population standard deviation is 3 days, what minimum sample size is needed to be 90% confident that the sample mean is within 1 day of the true population mean? z0.101.282z0.051.645z0.0251.960z0.0 12.326z0.0052.576 Use the table above for the z-score, and be sure to round up to the nearest integer.

The minimum sample size is needed to be 90% confident that the sample mean is within 1 day of the true population mean is 25.

Step-by-step explanation:

We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of .

So it is z with a pvalue of , so

Now, find the margin of error M as such

In which is the standard deviation of the population and n is the size of the sample.

If the population standard deviation is 3 days, what minimum sample size is needed to be 90% confident that the sample mean is within 1 day of the true population mean?

This is n when . So

Rouding up to the nearest integer, 25.

The minimum sample size is needed to be 90% confident that the sample mean is within 1 day of the true population mean is 25.

ruth is 6 years old

step-by-step explanation:

6 + 24 = 30,   so 6/30 = .2  

if you do 1/5 it also equals .2, so that is the answer.

i think that you should ask google for the answer to that problem because if we don't know it google does