Mathematics, 23.03.2020 21:19 astultz309459
Evaluate the given integral by changing to polar coordinates.∫∫ x2y dA, where D is the top half of the disk with center the origin and radius 5D
Answers: 3
.
and substitute in (1) we get,
then,![du=-\sin\theta d\theta\implies-du=\sin\thetad\theta[tex]For [tex]\theta=0, u=1](/tpl/images/0559/4819/6d518.png)
and 
gives u=-1. Hence,
![=\Big[\frac{u^3}{3}\Big]_{-1}^{1}\times\Big[\frac{r^5}{5}\Big]_{0}^{5}](/tpl/images/0559/4819/abb3c.png)
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Evaluate the given integral by changing to polar coordinates.∫∫ x2y dA, where D is the top half of t...
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