You need to borrow $1000. You can borrow it for 3 years at 8% simple interest, or for 2 years at 11% simple interest. Which loan will cost more? By how much?

He'll pay $ 20 more for the first loan.

Step-by-step explanation:

Since the loans are at a simple interest we can use this equation to compute the total amount that will be paid:

M = C(1 + i*t)

Where M is the total after interest, i is the rate at wich the loan was given and t is the amount of time.

For the first loan:

M = 1000*(1 + 0.08*3) = 1000*(1 + 0.24) = 1000*(1.24) = 1240 $

For the second loan:

M = 1000*(1 + 0.11*2) = 1000*(1 + 0.22) = 1000*(1.22) = 1220 $

The difference in price on the loans is 1240 - 1220 = 20 $

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

its c or d   take a lucky guess my dude