3x - 5y = -35
12x+y=-6

x =y =

Step-by-step explanation:

in order to solve this system of equation  let us say

3x - 5y = -35equation 1

12x+y=-6equation 2

from equation 2

12x+y=-6equation 2

y =  -6 - 12x equation 3

substitute for y = -6 -12x into equation 1

3x - 5y = -35equation 1

3x -5( -6 - 12x) = -35

3x + 30 + 60x = -35

63x + 30  = -35

collect like terms

63x= -35 -30

63x = - 65

divide both sides by 63

63h/63 = -65/ 63

x = -1.03

put x = 1. 03 into equation 3

y =  -6 - 12x equation 3

y = -6 - 12( -1.03)

y = -6 + 12.38

y = 6.38

d. 8

step-by-step explanation:

the given radical expression is:

we can rewrite this as:

we express as square numbers to get;

the exponents will now cancel out to give.

the correct answer is d

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92