About how many times more intense is an earthquake that measures 8.2 on the Richter scale than an earthquake that measures 7.3 on the Richter scale? Recall that Richter defined the magnitude R of an earthquake of intensity I to be
R = log I. (Round your answer to two decimal places.)

About 7.94 times

Step-by-step explanation:

The intensity of an earthquake can be found using the formula:

Where

I is the intensity

I_0 is intensity of magnitude 0 earthquake

M is Richter scale magnitude

For first quake, it will be:

For the second quake, it will be:

The times the intensity is more can be found by dividing both, so we have:

The first earthquake is about 7.94 times the second quake

570, the answer is 570, hope it

step-by-step explanation:

let's assume

number of candles set =x

price of of x candles =p(x)

we are given

a candle maker prices one set of scented candles at $10 and sells an average of 200 sets each week

so, we get point as (200,10)

he finds that when he reduces the price by $1, he then sells 50 more candle sets each week

so, we can find slope

now, we can use point slope form of line

now, we can plug values

we can use point

and find b

now, we can plug it back

and we get

now, we can find revenue

we know that

revenue = price*quantity

so, we get